document.write( "Question 1067171: A passenger train left San Diego and went to San Francisco and back. The trip to San Francisco took three hours, but the return trip took four hours. If the train averaged six kilometers per hour on the trip back to San Diego, find the average speed of the train during the outbound trip. \n" ); document.write( "
Algebra.Com's Answer #682364 by josgarithmetic(39618)\"\" \"About 
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Trip back took \"six kilometers per hour\"?
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document.write( "                  SPEED        TIME       DISTANCE\r\n" );
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document.write( "OUTBOUND          r             3           d\r\n" );
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document.write( "RETRURNING        6             4           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "The return-trip information tells you the one-way trip distance is \"6%2A4=d=24\", in kilometers. Does this really make sense to you?\r
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\n" ); document.write( "\n" ); document.write( "If you want to continue working with that, then the outbound trip information means \"r%2A3=d\",
\n" ); document.write( "\"r=d%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"r=24%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28r=8%29\", the outbound trip speed.\r
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\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "Suggestion: recheck the problem description, since some information may be wrong in your posted question.
\n" ); document.write( "NOTE: Distance between those two locations should be much nearer to 738 kilometers.
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