document.write( "Question 1067137: In Arithmetic series, the 3rd term is twice the 8th term. Find the sum of the first 25 terms \n" ); document.write( "
Algebra.Com's Answer #682341 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! The nth term of an arithmetic sequence is a(n) = a(1) + d(n-1), where a(1) is the first term and d is the common difference \n" ); document.write( ": \n" ); document.write( "a(3) = a(1) + d(3-1) \n" ); document.write( "a(8) = a(1) + d(8-1) \n" ); document.write( ": \n" ); document.write( "We are given \n" ); document.write( ": \n" ); document.write( "a(1) + 2d = 2(a(1) + 7d) \n" ); document.write( ": \n" ); document.write( "a(1) + 2d = 2a(1) + 14d \n" ); document.write( ": \n" ); document.write( "a(1) + 12d = 0 \n" ); document.write( ": \n" ); document.write( "a(1) = -12d \n" ); document.write( "a(25) = a(1) + d(25-1) \n" ); document.write( ": \n" ); document.write( "The sum of the first n terms of an arithmetic sequence is S(n) = (n/2)(a(1) + a(n)) \n" ); document.write( ": \n" ); document.write( "*************************************** \n" ); document.write( "S(25) = (25/2)(-12d + (-12d)+(24d)) = 0 \n" ); document.write( "*************************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |