document.write( "Question 1067133: The width of a rectangle is 5 yards less than the length. If the width were decreased by 2 yards the area would be decreased by 50 square yard. Find the length and width of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #682321 by josgarithmetic(39617)\"\" \"About 
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The width of a rectangle is 5 yards less than the length.
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\n" ); document.write( "\"w=L-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=wL\"
\n" ); document.write( "\"A=%28L-5%29L\"\r
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\n" ); document.write( "\n" ); document.write( " If the width were decreased by 2 yards the area would be decreased by 50 square yard.
\n" ); document.write( "----
\n" ); document.write( "Old area \"L%28L-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "New area \"L%28L-5-2%29\"
\n" ); document.write( "\"L%28L-7%29\"\r
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\n" ); document.write( "\n" ); document.write( "--- --- --- --- --- ---
\n" ); document.write( "Find the length and width of the original rectangle.
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\n" ); document.write( "\n" ); document.write( "\"L%28L-5%29-L%28L-7%29=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"L%5E2-5L-%28L%5E2-7L%29=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"L%5E2-5L-L%5E2%2B7L=50\"\r
\n" ); document.write( "\n" ); document.write( "\"2L=50\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28L=25%29\"\r
\n" ); document.write( "\n" ); document.write( "Return to given description for w.
\n" ); document.write( "\"w=L-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"w=25-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28w=20%29\"
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