document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1067104>Question 1067104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q) Find dy/dx for each of the following. \r<BR>\n" );
document.write( "\n" );
document.write( "a) y=-1/6(e^(-3x))+x(2x-1)\r<BR>\n" );
document.write( "\n" );
document.write( "b) 3x^(2)y-xy^2=sin^(2)3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682298 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  y=-1/6(e^(-3x))+x(2x-1); second term is 2x^2-x<BR>\n" );
document.write( "y'=(1/2)(e^(-3x))+4x-1<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "3x^2(dy/dx)+6xy-2xy(dy/dx)-y^2=2 sin (3x)*cos(3x)*3<BR>\n" );
document.write( "[3x2-2xy] (dy/dx)+6xy-y^2=6 sin(3x)(cos(3x))<BR>\n" );
document.write( "dy/dx=[6 sin (3x)*cos (3x)+y^2-6xy]/(3x^2-2xy)<BR>\n" );
document.write( "Note: 6 sin (3x)(cos(3x)=3sin (6x), because sin (2a)=2 sin (a) cos (a)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );