document.write( "Question 1066970: A tank of water has been outdoors in cold weather until a 6.00 cm thick slab of ice has formed on its surface. The air above the ice is at -17.0 degrees C. Calculate the rate of formation of ice (in centimeters/hour) on the bottom surface of the ice slab. Take the thermal conductivity of ice to be 0.0040 cal/s-cm-degree C, the density to be 0.92 g/cm^3, and the heat of fusion to be 80 cal/g. Assume that no heat enters or leaves the water through the walls of the tank.
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Algebra.Com's Answer #682219 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "A tank of water has been outdoors in cold weather until a 6.00 cm thick slab of ice has formed on its surface.
\n" ); document.write( "The air above the ice is at -17.0 degrees C. Calculate the rate of formation of ice (in centimeters/hour) on the bottom surface
\n" ); document.write( " of the ice slab. Take the thermal conductivity of ice to be 0.0040 cal/s-cm-degree C, the density to be 0.92 g/cm^3,
\n" ); document.write( "and the heat of fusion to be 80 cal/g. Assume that no heat enters or leaves the water through the walls of the tank.
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\n" ); document.write( "\n" ); document.write( "The units are not SI, but they all are consistent (!), so we can make all calculations from the beginning to the end
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document.write( "1.  The general balance equation is \r\n" );
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document.write( "    \"rho%2Aphi%2A%28dL%2Fdt%29\" = \"lambda%2A%28%28DELTA%28T%29%29%2FL%29\".\r\n" );
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document.write( "    The right side is the heat flow by conductivity from the water in the tank to the atmosphere through the ice layer: \r\n" );
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document.write( "    DELTA(T) is the temperature difference of 17 °C across the ice layer;  \r\n" );
document.write( "             (we assume that the water temperature in the tank is 0 °C under the ice layer)\r\n" );
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document.write( "    L = 6 cm is the layer thickness;\r\n" );
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document.write( "    \"lambda\" = 0.004 \"cal%2F%28s%2Acm_%2AdegC%29\" is the thermal conductivity of ice.\r\n" );
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document.write( "    The left side is the amount of heat to increase the thickness of the ice layer:\r\n" );
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document.write( "    \"%28dL%29%2F%28dt%29\" is the rate of the thickness increasing, in \"cm%2Fs\"; it is the value and the quantity under the problem question;\r\n" );
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document.write( "    \"phi\" is the specific latent heat of freezing, 80 \"cal%2Fg\";\r\n" );
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document.write( "    \"rho\" is the density of ice, 0.92 \"g%2Fcm%5E3\".\r\n" );
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document.write( "    You may check that the dimensions of both sides are consistent.\r\n" );
document.write( "    If you never did/check it before, make this very useful exercise. \r\n" );
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document.write( "2.  Now substitute all given data to get\r\n" );
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document.write( "    \"%28dL%29%2F%28dt%29\" = \"%280.004%2A%2817%2F6%29%29%2F%280.92%2A80%29\" = 0.000154 \"cm%2Fs\" = 0.554 \"cm%2Fhour\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The rate of formation of ice is 0.554 \"cm%2Fhour\" under the given condition.\r
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