document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12766>Question 12766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation and solve the following: Four times a number decreased by twice the number is 100. What is the number ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6822 by </B><A HREF=/tutors/aboutme.mpl?userid=elizabeth2005><B>elizabeth2005(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elizabeth2005><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation would be 4n-2n=100<BR>\n" );
document.write( "now you have to subtract 4n-2n which leaves you with 2n<BR>\n" );
document.write( "now you have to divide both sides by 2<BR>\n" );
document.write( "so 2n divided by 2 cancells out and leaves you with n<BR>\n" );
document.write( "now you have 100 divided by 2 which will be 50<BR>\n" );
document.write( "n=50\r<BR>\n" );
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document.write( "also you can check your work<BR>\n" );
document.write( "try it....<BR>\n" );
document.write( "4 times 50 is 200<BR>\n" );
document.write( "2 times 50 is 100<BR>\n" );
document.write( "200 minus 100 is 100\r<BR>\n" );
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document.write( "hope that helps you to understand </SPAN>\n" );
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