document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066920>Question 1066920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A group of children was playing cards and misplace the five of hearts, if a card is selected at random from the remaining 51 cards. Find the probability that the card is a<BR>\n" );
document.write( "a)	club.<BR>\n" );
document.write( "b)	five.<BR>\n" );
document.write( "c)	 five or club.<BR>\n" );
document.write( "d)	five of heart<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682192 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability it is a club is 13/51<BR>\n" );
document.write( "a 5 is 3/51 or 1/17<BR>\n" );
document.write( "a five or a club is probability of both - conjoined probability (1/51)=(13+3-1)/51=15/51 or 5/17.<BR>\n" );
document.write( "five of hearts is 0--it is missing.<BR>\n" );
document.write( "five or a heart (if that is what was meant) is 3/51+(12/51), and there is no conjoined probability since the H5 is missing  It is 15/51 or 5/17. </SPAN>\n" );
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