document.write( "Question 1066959: The width of a rectangle is 11 units less than the length. If the area is 60 square units, then find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #682183 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The width of a rectangle is 11 units less than the length. If the area is 60 square units, then find the dimensions of the rectangle. \n" ); document.write( "length = x \n" ); document.write( "width = x-11 \n" ); document.write( "------ \n" ); document.write( "Area = x(x-11) = 60 \n" ); document.write( "x^2-11x-60 = 0 \n" ); document.write( "------- \n" ); document.write( "(x-15)(x+4) = 0 \n" ); document.write( "Positive solution:: \n" ); document.write( "length = x = 15 units \n" ); document.write( "width = x-11 = 4 units \n" ); document.write( "---------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |