document.write( "Question 1066956: A watch loses 1 second every week. How many minutes will the watch be off at the end of 1 year? \n" ); document.write( "

Algebra.Com's Answer #682175 by josmiceli(19441) $\"\"$ $\"About$

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With 52 weeks in a year, $\"+1%2A52+=+52+\"$ sec
\n" ); document.write( " $\"+52+\"$ sec is $\"+52%2F60+\"$ min
\n" ); document.write( " $\"+52%2F60+=+13%2F15+\"$ min
\n" ); document.write( "The watch will be off $\"+13%2F15+\"$ min at
\n" ); document.write( "the end of 1 year\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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