document.write( "Question 1066954: where log2=0.3010 and log3=0.4771.evaluate without calculator log1.25 \n" ); document.write( "

Algebra.Com's Answer #682172 by Alan3354(69443) $\"\"$ $\"About$

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log(2) = 0.301 base 10
\n" ); document.write( "--------
\n" ); document.write( "1.25 = 1/8 = 1/(2^3)
\n" ); document.write( "log(1.25) = log(1) - 3*log(2)
\n" ); document.write( "= 0 - 0.903
\n" ); document.write( "= = -0.903\r
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