document.write( "Question 93659: I am stumped on this one. \r
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document.write( "Solve the system by addition. \r
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document.write( "-4x + 5y = 5
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document.write( "x - 2y = -2 \r
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document.write( "Could you help guide me on the right track? Thank you. \n" );
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Algebra.Com's Answer #68213 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve the system by addition. \n" ); document.write( "-4x + 5y = 5 \n" ); document.write( "x - 2y = -2 \n" ); document.write( "------------- \n" ); document.write( "If you solve it by substitution you proceed as follows: \n" ); document.write( "Solve the 2nd equation for x to get x = 2y-2 \n" ); document.write( "----------- \n" ); document.write( "Substitute that value into the 1st equation and solve for y, as follows: \n" ); document.write( "-4(2y-2)+5y = 5 \n" ); document.write( "-8y+8 + 5y = 5 \n" ); document.write( "-3y = -3 \n" ); document.write( "y = 1 \n" ); document.write( "------------- \n" ); document.write( "Substitute that into x = 2y-2 to solve for \"x\", as follows: \n" ); document.write( "x = 2*1 -2 \n" ); document.write( "x = 0 \n" ); document.write( "=============== \n" ); document.write( "Solution for the system (0,1) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |