document.write( "Question 93659: I am stumped on this one. \r
\n" ); document.write( "\n" ); document.write( "Solve the system by addition. \r
\n" ); document.write( "\n" ); document.write( "-4x + 5y = 5
\n" ); document.write( "x - 2y = -2 \r
\n" ); document.write( "\n" ); document.write( "Could you help guide me on the right track? Thank you.
\n" ); document.write( "

Algebra.Com's Answer #68213 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve the system by addition.
\n" ); document.write( "-4x + 5y = 5
\n" ); document.write( "x - 2y = -2
\n" ); document.write( "-------------
\n" ); document.write( "If you solve it by substitution you proceed as follows:
\n" ); document.write( "Solve the 2nd equation for x to get x = 2y-2
\n" ); document.write( "-----------
\n" ); document.write( "Substitute that value into the 1st equation and solve for y, as follows:
\n" ); document.write( "-4(2y-2)+5y = 5
\n" ); document.write( "-8y+8 + 5y = 5
\n" ); document.write( "-3y = -3
\n" ); document.write( "y = 1
\n" ); document.write( "-------------
\n" ); document.write( "Substitute that into x = 2y-2 to solve for \"x\", as follows:
\n" ); document.write( "x = 2*1 -2
\n" ); document.write( "x = 0
\n" ); document.write( "===============
\n" ); document.write( "Solution for the system (0,1)
\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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