document.write( "Question 93643: I am really having difficulty solving this problem:\r
\n" ); document.write( "\n" ); document.write( "Write the equation of the line with slope –2 and y-intercept (0, 0). Then graph the line.\r
\n" ); document.write( "\n" ); document.write( "Thanks for you help!
\n" ); document.write( "

Algebra.Com's Answer #68210 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-2\" which goes through the point (\"0\",\"0\"), you can simply use the point-slope formula to find the equation:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=%28-2%29%28x-0%29\" Plug in \"m=-2\", \"x%5B1%5D=0\", and \"y%5B1%5D=0\" (these values are given)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=-2x%2B%28-2%29%28-0%29\" Distribute \"-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=-2x%2B0\" Multiply \"-2\" and \"-0\" to get \"0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B0%2B0\" Add 0 to both sides to isolate y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B0\" Combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-2x\" Remove any zero terms\r
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-2\" which goes through the point (\"0\",\"0\") is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-2x\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-2\" and the y-intercept is \"b=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=-2x\" and plot the point (\"0\",\"0\"), we get (note: if you need help with graphing, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Graph of \"y=-2x\" through the point (\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-2\" and goes through the point (\"0\",\"0\"), this verifies our answer.
\n" ); document.write( "
\n" );