document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066871>Question 1066871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer mixed pecans worth $1.12 per pound with cashews worth $0.60 per pound. If she made 100 pounds of a mixture worth $0.73 per pound, how many pounds of pecans are in the mixture? I have tried many times to solve this problem and I cant get it wrong otherwise I get a 0. If you can give me the equations to use I can solve it easily. I have tried the equation 1.12p+.6c=100*.73 and p+c=100 but I get a repeating decimal that doesnt work. thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682094 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=pecans, y=cashews<BR>\n" );
document.write( "x+y=100<BR>\n" );
document.write( "1.12x+0.60y=100*0.73=73<BR>\n" );
document.write( "x+y=100<BR>\n" );
document.write( "x=100-y<BR>\n" );
document.write( "1.12(100-y)+0.60 y=73<BR>\n" );
document.write( "112-1.12y+0.60y=73<BR>\n" );
document.write( "-0.52y=-39<BR>\n" );
document.write( "y=75 pounds of cashews @0.60=$45<BR>\n" );
document.write( "x=25 pounds of pecans @1.12=$28<BR>\n" );
document.write( "Total $73.<BR>\n" );
document.write( "You set it up fine.  I did substitution, but you could do elimination. </SPAN>\n" );
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