document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066863>Question 1066863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man has two investments, one paying 5% annual interest and the other at 8%. The total annual income from the two investments is P 4,650. If the interest rates were interchanged, the total annual income would be P 5,100. Find the amount invested. of each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682093 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y are the two amounts.<BR>\n" );
document.write( ".05x+.08y=4650<BR>\n" );
document.write( ".08x+.05y=5100<BR>\n" );
document.write( "5x+8y=465000, multiplying by 100<BR>\n" );
document.write( "8x+5y=510000<BR>\n" );
document.write( "Multiply the top by -8 and the bottom by +5 to eliminate x<BR>\n" );
document.write( "-40x-64y=-3720000<BR>\n" );
document.write( "40x+25y=2550000<BR>\n" );
document.write( "-39y=-1170000<BR>\n" );
document.write( "y=P30000<BR>\n" );
document.write( "5x+240000=465000<BR>\n" );
document.write( "5x=225000<BR>\n" );
document.write( "x=P45000<BR>\n" );
document.write( ".05(45000)+.08(30000)=2250+2400=4650<BR>\n" );
document.write( ".08(45000)+.05(30000)=3600+1500=5100 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );