document.write( "Question 1066867: I need help to solve the following for x: \"+p%5E2%281-x%29-2pqx=q%5E2%281%2Bx%29\"
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Algebra.Com's Answer #682087 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Simplify and isolate terms of x.\r
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\n" ); document.write( "\n" ); document.write( "\"p%5E2-%28p%5E2%29x-2pqx=q%5E2%2B%28q%5E2%29x\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%5E2-%28p%5E2%29x-2pqx-%28q%5E2%29x=q%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-%28p%5E2%29x-2pqx-%28q%5E2%29x=q%5E2-p%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Multiplication both sides negative 1:
\n" ); document.write( "\"%28p%5E2%29x%2B2pqx%2B%28q%5E2%29x=p%5E2-q%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28p%5E2%2B2pq%2Bq%5E2%29=p%5E2-q%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28p%5E2-q%5E2%29%2F%28p%5E2%2B2pq%2Bq%5E2%29\"
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