document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066832>Question 1066832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph y=-3 3x+y=6. Need to see steps.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682081 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-3 is a horizontal line along the line y=-3. The slope is 0.<BR>\n" );
document.write( "3x+y=6<BR>\n" );
document.write( "y=-3x+6<BR>\n" );
document.write( "This is a line with intercept 6, so the point (0,6) is on it. The slope is -3 so that is down 3 and to the right 1 or to  the left 1 and up 3.  It slopes steeply down to the right because it is large negative.<BR>\n" );
document.write( "put in 1 for x and -3+6=3 for y: (-1,3) is a point.<BR>\n" );
document.write( "You can go to the original 3x+y=6 and get 2 points: Let x=0 and y=6.  Let y=0 and x=2.  The points are (0,6) and (2,0).  That is because when x=0 the equation is y=6 and when y=0 the equation is 3x=6.<BR>\n" );
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