document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93655>Question 93655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After the first term, each term in a sequence is 3 greater than 1/3 of the preceeding term. If t is the first term of the sequence and t (cannot be = to) 0, what is the ratio of the second term to the first term?\r<BR>\n" );
document.write( "\n" );
document.write( "(A) t+9/3<BR>\n" );
document.write( "(B) t+3/3<BR>\n" );
document.write( "(C) t+9/3t<BR>\n" );
document.write( "(D) t+3/3t<BR>\n" );
document.write( "(E) 9-2t/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68208 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After the first term, each term in a sequence is 3 greater than 1/3 of the preceeding term. If t is the first term of the sequence and t (cannot be = to) 0, what is the ratio of the second term to the first term? <BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "1st term = \"t\"<BR>\n" );
document.write( "2nd term = (1/3)t + 3<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Ratio = [(1/3)t+3]/t = (1/3) + (3/t) = (t+9)/3t\r<BR>\n" );
document.write( "\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );