document.write( "Question 93610: If you were to throw an object straight up from a platform 50 feet high, at an initial velocity of 80 feet per second, the height of that object in feet above the ground t seconds after you released it would be described as follows:\r
\n" ); document.write( "\n" ); document.write( "Height = -16*t^2 + 80*t + 50\r
\n" ); document.write( "\n" ); document.write( "How high will tge object be 3.5 seconds after released? \r
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Algebra.Com's Answer #68201 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If you were to throw an object straight up from a platform 50 feet high, at an initial velocity of 80 feet per second, the height of that object in feet above the ground t seconds after you released it would be described as follows:
\n" ); document.write( ":
\n" ); document.write( "Height = -16*t^2 + 80*t + 50
\n" ); document.write( ":
\n" ); document.write( "How high will the object be 3.5 seconds after released?
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\n" ); document.write( "Substitute 3.5 for t and find the height:
\n" ); document.write( "h = -16(3.5^2) + 80(3.5) + 50
\n" ); document.write( "h = -16(12.25) + 280 + 50
\n" ); document.write( "h = -196 + 280 + 50
\n" ); document.write( "h = 134 ft high in 3.5 sec \n" ); document.write( "

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