document.write( "Question 1066798: Please help me solve the question, Pete, Bryan and Philip are cousins. Pete age is one third of Bryan and Philip is 5 older than Bryan. The sum of the ages of the coudins is 40. Find the ages of each \n" ); document.write( "
Algebra.Com's Answer #682008 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let Bryan's age be x, then \n" ); document.write( ": \n" ); document.write( "Pete's age is x/3 and \n" ); document.write( ": \n" ); document.write( "Philip's age is x+5 \n" ); document.write( ": \n" ); document.write( "x + (x/3) +x+5 = 40 \n" ); document.write( ": \n" ); document.write( "(7x/3) = 35 \n" ); document.write( ": \n" ); document.write( "7x = 105 \n" ); document.write( ": \n" ); document.write( "x = 15 \n" ); document.write( ": \n" ); document.write( "************************************* \n" ); document.write( "Pete's age is 15/3 = 5 years old \n" ); document.write( "Bryan's age is 15 years old \n" ); document.write( "Philip's age is 15+5 = 20 years old \n" ); document.write( ": \n" ); document.write( "check answer \n" ); document.write( ": \n" ); document.write( "5 + 15 + 20 = 40 \n" ); document.write( "40 = 40 \n" ); document.write( ": \n" ); document.write( "our answer checks \n" ); document.write( "************************************ \n" ); document.write( ": \n" ); document.write( " |