document.write( "Question 1066798: Please help me solve the question, Pete, Bryan and Philip are cousins. Pete age is one third of Bryan and Philip is 5 older than Bryan. The sum of the ages of the coudins is 40. Find the ages of each \n" ); document.write( "
Algebra.Com's Answer #682008 by rothauserc(4718)\"\" \"About 
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let Bryan's age be x, then
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\n" ); document.write( "Pete's age is x/3 and
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\n" ); document.write( "Philip's age is x+5
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\n" ); document.write( "x + (x/3) +x+5 = 40
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\n" ); document.write( "(7x/3) = 35
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\n" ); document.write( "7x = 105
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\n" ); document.write( "x = 15
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\n" ); document.write( "Pete's age is 15/3 = 5 years old
\n" ); document.write( "Bryan's age is 15 years old
\n" ); document.write( "Philip's age is 15+5 = 20 years old
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\n" ); document.write( "5 + 15 + 20 = 40
\n" ); document.write( "40 = 40
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