document.write( "Question 1066781: If each side of square is increased by 5 cm, the total area of both the new square and the original square will be 200 cm2. Approximate to the nearest tenth of a centimeter the length of each side of the original square. \n" ); document.write( "
Algebra.Com's Answer #681994 by josgarithmetic(39617)\"\" \"About 
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FOUR sides on a square shape. Still, increase each side by 5 units means increasing each dimension (two of them) by 5 units each.\r
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\n" ); document.write( "\n" ); document.write( "Old square:
\n" ); document.write( "\"x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "New square:
\n" ); document.write( "\"%28x%2B5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Both areas together given as \"200%2Acm%5E2\"
\n" ); document.write( "\"x%5E2%2B%28x%2B5%29%5E2=200\"
\n" ); document.write( "Simplify this and solve.
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\n" ); document.write( "\"2x%5E2%2B10x%2B25=200\"
\n" ); document.write( "\"2x%5E2%2B10x-175=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-10%2Bsqrt%28100%2B4%2A2%2A175%29%29%2F%282%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-10%2B10sqrt%2815%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-5%2B5%2Asqrt%2815%29%29%2F2\"
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