document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066758>Question 1066758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You Have to answer 3 essay questions for an exam . There are 5 essays to choose from . How many different groups of 3 essays could you possibly choose ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681984 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If order mattered, then you'd have 5*4*3 = 20*3 = 60 different possible permutations\r<BR>\n" );
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document.write( "However, order doesn't matter. So there are 60/(3!) = 60/(3*2*1) = 60/6 = 10 different combinations possible.\r<BR>\n" );
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document.write( "The final answer is 10. </SPAN>\n" );
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