document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93561>Question 93561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completeley\r<BR>\n" );
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document.write( "10a^2+ab-2b^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68198 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOU NEED TO FIND A SET OF FACTORS FROM THE NUMBERS 10 &-2 THAT WNEM MULTIPLIED TOGETHER AND THEN ADDED WILL=1.<BR>\n" );
document.write( "FACTORS FOR 10=1&10,-1&-10,2&5,-2&-5.<BR>\n" );
document.write( "FACTORS FOR -2=1&-2,-1&2.<BR>\n" );
document.write( "THESE ARE ALL POSSIBLE FACTORS. <BR>\n" );
document.write( "NOW SELECT ONE FACTOR FROM EACH GROUP & MULTIPLY IT BY ONE FACTOR FROM THE OTHER SET & ADD THE PRODUCTS. WHEN YOU GET A SUM OF 1 THEN YOU HAVE THE ANSWER.<BR>\n" );
document.write( "1*1+10*-2=1-20=-19 IS NOT A GOOD CHOICE.<BR>\n" );
document.write( "2*-1+5*2=-2+10=8 IS NOT A GOOD CHOICE.<BR>\n" );
document.write( "5*1+2*-2=5-4=1 LOOKS LIKE A WINNER.<BR>\n" );
document.write( "NOW USEING THE OUTER & INNER ITEMS OF THE FOIL PROCEDURE WE GET:<BR>\n" );
document.write( "OUTER=5*1=5 INNER=-2*2-4 NOW ADD 5-4=1 THE MIDDLE TERM OF THE EQUATION.<BR>\n" );
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document.write( "10a^2+ab-2b^2<BR>\n" );
document.write( "(5a-2b)(2a+b) </SPAN>\n" );
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