document.write( "Question 1066694: A fraction becomes 1/2 if 1 is added to both numerator and dnominator and if 1 is subtracted from both its numerator and denominator ,it becomes 1/3 .Find the fraction. \n" ); document.write( "

Algebra.Com's Answer #681910 by Fombitz(32388) $\"\"$ $\"About$

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OK, let the fraction be $\"A%2FB\"$ .
\n" ); document.write( " $\"%28A%2B1%29%2F%28B%2B1%29=1%2F2\"$
\n" ); document.write( " $\"2%28A%2B1%29=B%2B1\"$
\n" ); document.write( " $\"2A%2B2=B%2B1\"$
\n" ); document.write( "1. $\"2A-B=-1\"$
\n" ); document.write( "and
\n" ); document.write( " $\"%28A-1%29%2F%28B-1%29=1%2F3\"$
\n" ); document.write( " $\"3%28A-1%29=B-1\"$
\n" ); document.write( " $\"3A-3=B-1\"$
\n" ); document.write( "2. $\"3A-B=2\"$
\n" ); document.write( "Subtracting 1 from 2,
\n" ); document.write( " $\"3A-B-%282A-B%29=2-%28-1%29\"$
\n" ); document.write( " $\"3A-B-2A%2BB=2%2B1\"$
\n" ); document.write( " $\"A=3\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"2%283%29-B=-1\"$
\n" ); document.write( " $\"6-B=-1\"$
\n" ); document.write( " $\"B=6%2B1\"$
\n" ); document.write( " $\"B=7\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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