document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066684>Question 1066684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation. (&#8730;5x+39)-8=3x-15<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681906 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your original equation is sqrt(5x + 39) - 8 = 3x - 15\r<BR>\n" );
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document.write( "add 8 to both sides of the equation to get sqrt(5x + 39) = 3x - 7\r<BR>\n" );
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document.write( "square both sides of the equation to get 5x + 39 = (3x - 7)^2\r<BR>\n" );
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document.write( "simplify to get 5x + 39 = 9x^2 - 42x + 49\r<BR>\n" );
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document.write( "subtract (5x + 39) from both sides of the equation to get 0 = 9x^2 - 47x + 10\r<BR>\n" );
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document.write( "factor the right side of the equation to get 0 = (x - 5) * (9x - 2)\r<BR>\n" );
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document.write( "solve for x to get x = 5 or x = 2/9\r<BR>\n" );
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document.write( "replace x in your original equation to see if these possible solutions are good.\r<BR>\n" );
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document.write( "your original equation is sqrt(5x + 39) - 8 = 3x - 15\r<BR>\n" );
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document.write( "when x = 5, this equation becomes sqrt(5*5 + 39) - 8 = 3*5 - 15.\r<BR>\n" );
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document.write( "evaluate both sides of this equation to get sqrt(64) - 8 = 15 - 15.\r<BR>\n" );
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document.write( "simplify to get 0 = 0\r<BR>\n" );
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document.write( "x = 5 is one of the solutions to your original equation.\r<BR>\n" );
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document.write( "when x = 2/9, this equation becomes sqrt(5 * 2/9 + 39) - 8 = 3 * 2/9 - 15\r<BR>\n" );
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document.write( "evaluate both sides of this equation to get sqrt(10/9 + 39) - 8 = 6/9 - 15\r<BR>\n" );
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document.write( "simplify to get 6 and 1/3 = -14 and 1/3.\r<BR>\n" );
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document.write( "this is not a true equaation, therefore x = 2/9 is not a solution to your original equation.\r<BR>\n" );
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document.write( "the solution to your original equation is x = 5.\r<BR>\n" );
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document.write( "you can see this graphically by graphing both equations.\r<BR>\n" );
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document.write( "the first equation to graph is y = 3x - 15\r<BR>\n" );
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document.write( "the second equation to graph is y = sqrt(5x+39)-8\r<BR>\n" );
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document.write( "the graph looks like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2017/020303.jpg\" alt=\"$$$\" <</>\r<BR>\n" );
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document.write( "the intersection point of the graph of these 2 equations is only at x = 5.<BR>\n" );
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