document.write( "Question 1066667: A factory can produce two products, x and y, with a profit approximated by P =
\n" ); document.write( "14x + 24y – 900. The production of y must exceed the production of x by at least 100 units. Moreover, production levels are limited by the formula x + 2y ≤ 1400.\r
\n" ); document.write( "\n" ); document.write( "a. Identify the vertices of the feasible region.\r
\n" ); document.write( "\n" ); document.write( "b. What production levels yield the maximum profit, and what is the maximum profit?
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Algebra.Com's Answer #681904 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your profit equation is p = 14x + 24y - 900\r
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\n" ); document.write( "\n" ); document.write( "your constraint equations are:\r
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\n" ); document.write( "\n" ); document.write( "x + 2y <= 1400
\n" ); document.write( "y >= x + 100
\n" ); document.write( "x >= 0
\n" ); document.write( "y >= 0\r
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\n" ); document.write( "\n" ); document.write( "in the www.desmos.com calculator, you can do the following.\r
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\n" ); document.write( "\n" ); document.write( "graph the REVERSE inequalities.\r
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\n" ); document.write( "\n" ); document.write( "if the equation says > you would graph <.
\n" ); document.write( "if the equation says >=, you would graph <=.
\n" ); document.write( "if the equation says =, you would graph =.\r
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\n" ); document.write( "\n" ); document.write( "the software will shade the areas of the graph that are NOT in the feasible region.\r
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\n" ); document.write( "\n" ); document.write( "the region of feasible region will be the areas of the graph that are not shaded.\r
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\n" ); document.write( "\n" ); document.write( "you could do it directly, but spotting the region of feasibility is easier when you graph the reverse inequalities.\r
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\n" ); document.write( "\n" ); document.write( "try it yourself.\r
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\n" ); document.write( "\n" ); document.write( "you will see what i mean.\r
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\n" ); document.write( "\n" ); document.write( "in fact, i'll show you two graphs.\r
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\n" ); document.write( "\n" ); document.write( "the first graphs the opposite of the region of feasibility.\r
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\n" ); document.write( "\n" ); document.write( "the second graphs the region of feasibility.\r
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\n" ); document.write( "\n" ); document.write( "in the first graph, you will graph:\r
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\n" ); document.write( "\n" ); document.write( "x + 2y >= 1400
\n" ); document.write( "y <= x + 100
\n" ); document.write( "x <= 0
\n" ); document.write( "y <= 0\r
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\n" ); document.write( "\n" ); document.write( "this is opposite of the region of feasibility.
\n" ); document.write( "the unshaded area is the region of feasibility.\r
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\n" ); document.write( "\n" ); document.write( "in the second graph, you will graph:\r
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\n" ); document.write( "\n" ); document.write( "x + 2y <= 1400
\n" ); document.write( "y >= x + 100
\n" ); document.write( "x >= 0
\n" ); document.write( "y >= 0\r
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\n" ); document.write( "\n" ); document.write( "the shaded areas is the region of feasibility.\r
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\n" ); document.write( "\n" ); document.write( "desmos calculator can be found at www.desmos.com/calculator\r
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\n" ); document.write( "\n" ); document.write( "in both cases, the vertices of the region of feasibility are:\r
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\n" ); document.write( "\n" ); document.write( "(0,700)
\n" ); document.write( "(0,100)
\n" ); document.write( "(400,500)\r
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\n" ); document.write( "\n" ); document.write( "you will analyze the objective function of P = 14x + 24y - 900 at each of the intersection points.\r
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\n" ); document.write( "\n" ); document.write( "you will get:\r
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\n" ); document.write( "\n" ); document.write( "(0,700) = 15,900
\n" ); document.write( "(0,100) = 1,500
\n" ); document.write( "(400,500) = 16,700\r
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\n" ); document.write( "\n" ); document.write( "your maximum profit is when x = 400 and y = 500\r
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\n" ); document.write( "\n" ); document.write( "the constraints also have to be satisfied.\r
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\n" ); document.write( "\n" ); document.write( "y must be greater than x by 100.
\n" ); document.write( "since y = 500 and x = 400, this constraint is satisfied.\r
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\n" ); document.write( "\n" ); document.write( "x + 2y must be smaller than or equal to 1400.
\n" ); document.write( "since = 400 and y = 500, then x + 2y = 400 + 1000 = 1400.
\n" ); document.write( "this constraint is satisfied also.\r
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\n" ); document.write( "\n" ); document.write( "the graphs are shown below:
\n" ); document.write( "first graph shows inequalities opposite to those required.
\n" ); document.write( "second graph shows inequalities directly to those required.
\n" ); document.write( "first graph is easier to see the region of feasibility in my opinion.\r
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