document.write( "Question 1066686: 4. A triangular logo that is painted on the side of a building has a base length of 8 feet and a height of 4 yards. What is the area of the logo in square \n" ); document.write( "

Algebra.Com's Answer #681903 by math_helper(2461) $\"\"$ $\"About$

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Area of a triangle A is $\"+A+=+%281%2F2%29b%2Ah+\"$
\n" ); document.write( " where b = base and h = height\r
\n" ); document.write( "\n" ); document.write( "We are given base = b = 8ft
\n" ); document.write( " and height = h = 4yds\r
\n" ); document.write( "\n" ); document.write( "Before we calculate the area, we need to make sure all units are consistent:
\n" ); document.write( " h = 4yds = 4 yds * 3ft/yd = 12 ft
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\n" ); document.write( "\n" ); document.write( "So $\"+A+=+%281%2F2%29%288%29%2812%29+=+48+\"$ sq ft.\r
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\n" ); document.write( "Ans: $\"+A+=+highlight%2848%29+\"$ sq ft.\r
\n" ); document.write( "\n" ); document.write( "If you want the area in square yards (the question is cut off), just divide the above answer by 9 (=3ft/yd*3ft/yd = 9sq ft/sq yd)
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