document.write( "Question 1066673: A copper wire when bent in the form of a square encloses an area of 121 sq.cm .if the same wire is bent into the form of a circle ,then find the area of the circle .(use π=22/7).
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #681884 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Side of the square, 11 cm.
\n" ); document.write( "Length of the wire, 44 cm.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The circle formed will have perimeter or CIRCUMFERENCE 44 cm.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "r, radius
\n" ); document.write( "\"2%2Api%2Ar=44\"
\n" ); document.write( "-
\n" ); document.write( "\"pi%2Ar%5E2\"-------will be the formula for area.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"r=22%2Fpi\"
\n" ); document.write( "-
\n" ); document.write( "AREA, \"pi%2822%2Fpi%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"22%5E2%2Fpi\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"484%2Fpi\"
\n" ); document.write( "
\n" );