document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066660>Question 1066660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cathy and Ernie had four consecutive even integers. They found that the product of the second and fourth was 16 less than the product of -3 and the sum of the first and third. What were their integers?\r<BR>\n" );
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document.write( "I got X^2 +8x+12=-6x-28. Then:x^2 +14x+40=0. Next: (x+4)(x+10)=0. Finally: x=-4, x=-10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681870 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x,x+2,x+4,and x+6<BR>\n" );
document.write( "x^2+8x+12+16=-3(2x+4)<BR>\n" );
document.write( "x^2+8x+28=-6x-12<BR>\n" );
document.write( "x^2+14x+40=0<BR>\n" );
document.write( "(x+10)(x+4)=0, as you got<BR>\n" );
document.write( "-10,-8,-6,-4.<BR>\n" );
document.write( "product of second and fourth is 32 and that is 16 fewer than -3(-16)=48<BR>\n" );
document.write( "try<BR>\n" );
document.write( "-4,-2,0,2<BR>\n" );
document.write( "product of second and fourth is -4 and that is 16 fewer than -3(-4)=12<BR>\n" );
document.write( "Two solutions you have above work.\r<BR>\n" );
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