document.write( "Question 1066554: The length of a rectangle is 10m less than 3 times the width. If its width were increased by 20m and its length decreased by 15m. Its new area would be 175 sq. More than the original. Find the dimentions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #681862 by josgarithmetic(39617)\"\" \"About 
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Original rectangle
\n" ); document.write( "Width w
\n" ); document.write( "Length L
\n" ); document.write( "\"L=3w-10\"
\n" ); document.write( "Area, \"wL=w%283w-10%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "New rectangle
\n" ); document.write( "Width \"w%2B20\"
\n" ); document.write( "Length \"L-15=3w-10-15=3w-25\"
\n" ); document.write( "Area, \"%28w%2B20%29%283w-25%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"newRectangleArea-originalRectangleArea=175\"
\n" ); document.write( "\"highlight_green%28%28w%2B20%29%283w-25%29-w%283w-10%29=175%29\"
\n" ); document.write( "Simplify this and solve for w...
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