document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066653>Question 1066653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The units’ digit of a two-digit number is 7 more than the tens’ digit. If 26 is added to the number, the result obtained is five times the sum of the digits. Find the number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681859 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a = unit's digit<BR>\n" );
document.write( "Let b = ten's digit<BR>\n" );
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document.write( "In this way,  10b+a = the unknown number<BR>\n" );
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document.write( "   a = b+7    (1)<BR>\n" );
document.write( "  (10b+a) + 26 = 5(a+b)   (2)\r<BR>\n" );
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document.write( "Subs \"b+7\" for \"a\" from (1), into (2):<BR>\n" );
document.write( "(10b + (b+7)) + 26 = 5((b+7) + b)\r<BR>\n" );
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document.write( "(10b + b + 7 + 26) = 5(2b+7)<BR>\n" );
document.write( "11b + 33 = 10b + 35<BR>\n" );
document.write( " 11b + 33 - 10b - 33 = 10b + 35 - 10b - 33   (subtract 33 & 10b from both sides)<BR>\n" );
document.write( "                       b = 2\r<BR>\n" );
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document.write( "b=2 —(from (1))—>  a = 2+7 = 9<BR>\n" );
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document.write( "Ans:  the number is 29<BR>\n" );
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document.write( "Check:   2+9 = 11, and 11*5 = 55<BR>\n" );
document.write( "          and   29 + 26 = 55   (ok)\r<BR>\n" );
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