document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066611>Question 1066611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplifying\r<BR>\n" );
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document.write( "  -6/9-3 square root 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681853 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If this is -6/(9-3 sqrt(3))<BR>\n" );
document.write( "multiply top and bottom by the conjugate, which is 9+3 sqrt (3); the conjugate product is the square of the first term minus the square of the second term, or 9^2-9*3<BR>\n" );
document.write( "-6 (9+3 sqrt (3))/(81-27)<BR>\n" );
document.write( "-18(3+sqrt(3))/54<BR>\n" );
document.write( "-3 sqrt (3)/3 </SPAN>\n" );
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