document.write( "Question 1066637: the distance between two villages P and Q is x km . A train running between P and Q arrives 3 minutes behind the scheduled time when it travel at an average speed of 45km/h but arrives 9 minutes ahead of the scheduled time when it travels at an average speed of 60km/h,
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Algebra.Com's Answer #681842 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "the distance between two villages P and Q is x km . A train running between P and Q arrives 3 minutes behind the scheduled time
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\n" ); document.write( "ii) calculate the scheduled time for the journey
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document.write( "The travel time at the speed of 45 km/h is \"x%2F45\".\r\n" );
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document.write( "The travel time at the speed of 60 km/h is \"x%2F60\".\r\n" );
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document.write( "The time at the speed 45 km/h is in 3+9 = 12 minutes longer than at the speed 60 km/h.\r\n" );
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document.write( "It gives you a \"time\" equation:\r\n" );
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document.write( "\"x%2F45+-+x%2F60\" = \"1%2F5\".\r\n" );
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document.write( "To solve it, multiply both sides by 180. You will get\r\n" );
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document.write( "4x - 3x = 36.\r\n" );
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document.write( "x = 36.\r\n" );
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document.write( "Thus you just found the distance. It is 36 kilometers.\r\n" );
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document.write( "The time spent at the speed of 45 km/h was \"36%2F45\" = \"4%2F5\" of an hour = 48 minutes.\r\n" );
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document.write( "It was in 3 minutes longer than the scheduled time.\r\n" );
document.write( "Hence, the scheduled time is 48-3 = 45 minutes.\r\n" );
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\n" ); document.write( "\n" ); document.write( "All question are answered. The problem is solved.\r
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\n" ); document.write( "\n" ); document.write( "For similar solved problems see the lesson\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Travel and distance\".\r
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