document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93582>Question 93582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations. Determine the number of solutions for each.<BR>\n" );
document.write( "{1/3x+y=9<BR>\n" );
document.write( "{-2x+2y=-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68184 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "2/3x+2y=18    Multiply 2 times the upper equation<BR>\n" );
document.write( " -2x+2y=-6  <BR>\n" );
document.write( "----------<BR>\n" );
document.write( "8/3x   =24    Subtract the lower equation from the upper<BR>\n" );
document.write( "      x=9     Multply both sides times 3/8<BR>\n" );
document.write( "(-2*9)+2y=-6  Substitute 9 for x in either of the 2 equations<BR>\n" );
document.write( "       2y=12  Add 18 to both sides<BR>\n" );
document.write( "        y=6   Divide both sides by 2.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );