document.write( "Question 1066618: start with an equilateral triangle ABC of a side of 2 units and construct three outward-pointing squares ABPQ, BCTU, CARS and the three sides AB, BC and CA. what is the area of the hexagon PQRSTU? \n" ); document.write( "
Algebra.Com's Answer #681839 by KMST(5328)\"\" \"About 
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The hexagon is made up of
\n" ); document.write( "1 central equilateral triangle of side length 2,
\n" ); document.write( "3 squares of side length 2, and
\n" ); document.write( "3 isosceles triangles sharing sides of length 2 with the squares.
\n" ); document.write( "The surface area of each square is \"2%5E2=4\" .
\n" ); document.write( "The surface area of any triangle ABC can be calculated as
\n" ); document.write( "\"%281%2F2%29%2AAB%2ABC%2Asin%28B%29\" .
\n" ); document.write( "For the central, equilateral triangle ABC,
\n" ); document.write( "all sides have equal length, and all angles have the same measure:
\n" ); document.write( "\"AB=BC=AC=2\" and \"A=B=C=60%5Eo\" .,
\n" ); document.write( "so .
\n" ); document.write( "The angle between the squares measures
\n" ); document.write( "\"120%5Eo=360%5Eo-%2890%5Eo%2B60%5Eo%2B90%5Eo%29\" ,
\n" ); document.write( "because it completes \"360%5Eo\" when added to
\n" ); document.write( "the right angles of two squares,
\n" ); document.write( "plus a \"60%5Eo\" angle of the central equilateral triangle.
\n" ); document.write( "So each of the three outside isosceles triangles have
\n" ); document.write( "two sides of length 2 flanking an angle measuring \"120%5Eo\" ,
\n" ); document.write( "so the area of each of those 3 isosceles triangles is
\n" ); document.write( " .
\n" ); document.write( "Since the area of the hexagon is the sum of the areas of
\n" ); document.write( "\"3\" squares, each with \"area%28square%29=4\" ,
\n" ); document.write( "and \"4\" triangles, each with \"area%28triangle%29=sqrt%283%29\" ,
\n" ); document.write( "\"area%28hexagon%29=3%2A4%2B4%2Asqrt%283%29=highlight%2812%2B4sqrt%283%29%29\" .\r
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