document.write( "Question 1066627: A company is mixing a blend of two different coffees. The first kind (x) costs $8 a pound, and the second (y) costs $5 per pound. How much of each should they use if they want 60 pounds worth $6.25 per pound? \n" ); document.write( "

Algebra.Com's Answer #681827 by jorel1380(3719) $\"\"$ $\"About$

You can put this solution on YOUR website!
You have two different coffees. If the first is x, and the second is y, then y=60-x. So:
\n" ); document.write( "8x+5(60-x)=6.25(60)
\n" ); document.write( "3x+300=375
\n" ); document.write( "3x=75
\n" ); document.write( "x=25
\n" ); document.write( "y=35
\n" ); document.write( "The company wants 25 lbs. of the first coffee for every 35 lbs. of the second. ☺☺☺☺ \n" ); document.write( "

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