document.write( "Question 1066555: The length of a rectangle exceeds its width by 6 units. If each dimension were increased by 3 units. The area would be increased by 57 square units. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #681815 by ikleyn(52853) $\"\"$ $\"About$

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document.write( "l = w+6\r\n" );
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document.write( "area = w(w+6) = w^2+6w\r\n" );
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document.write( "(w+3)(w+9)-(w^2+6w)=57\r\n" );
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document.write( "w^2+12w+27-w^2-6w = 57\r\n" );
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document.write( "6w+27 = 57\r\n" );
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document.write( "6w = 30\r\n" );
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document.write( "w = 5 units\r\n" );
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document.write( "l = 11 units, area = 55 u^2\r\n" );
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