document.write( "Question 1066609: A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s=−16t^2+v0t. Find the time(s) that the projectile will (a) reach a height of 96 ft and (b) return to the ground when v0 = 112 feet per second. \n" ); document.write( "
Algebra.Com's Answer #681801 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! s=-16t^2+112t \n" ); document.write( "96=-16t^2+112t \n" ); document.write( "0=-16(t^2-7t+6), moving the 96 over and dividing everything by -16 \n" ); document.write( "(t-6)(t-1)=0 \n" ); document.write( "t=1, 6 seconds on the parabola. \n" ); document.write( "It hits the ground when s=0 and -16t^2+112t=0; -16t(t-7)=0; t=7 seconds. t=0, of course, because it started there.\r \n" ); document.write( "\n" ); document.write( " |