document.write( "Question 1066609: A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air​ resistance, its height in feet t seconds after launch is given by s=−16t^2+v0t. Find the​ time(s) that the projectile will​ (a) reach a height of 96 ft and​ (b) return to the ground when v0 = 112 feet per second. \n" ); document.write( "
Algebra.Com's Answer #681801 by Boreal(15235)\"\" \"About 
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s=-16t^2+112t
\n" ); document.write( "96=-16t^2+112t
\n" ); document.write( "0=-16(t^2-7t+6), moving the 96 over and dividing everything by -16
\n" ); document.write( "(t-6)(t-1)=0
\n" ); document.write( "t=1, 6 seconds on the parabola.
\n" ); document.write( "It hits the ground when s=0 and -16t^2+112t=0; -16t(t-7)=0; t=7 seconds. t=0, of course, because it started there.\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C200%2C-16x%5E2%2B112x%29\"
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