document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066546>Question 1066546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A forewheel of a carrier makes 6 revolution more than the  rear wheel in going 120meter. If the diameter of fore wheel be increased by 1/4th it's present duameter and diameter of rearwheel increases by 1/5th  ot it's present diameter . The forewheel will make 4 revolution than rearwheel in same direction? Find the circumference. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681772 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have two equations in two unknowns<BR>\n" );
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document.write( "let d(1) be the diameter of the fore wheel<BR>\n" );
document.write( "let d(2) be the diameter of the rear wheel<BR>\n" );
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document.write( "the circumference(C) of each wheel equals one revolution<BR>\n" );
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document.write( "the carrier goes 120 meters, then<BR>\n" );
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document.write( "1) (120 / (pi * d(1)) = (120 / (pi * d2)) + 6<BR>\n" );
document.write( "2) (120 / (pi * 5 * d(1) / 4)) = (120 / (pi * 6 * d(2) / 5) + 4<BR>\n" );
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document.write( "simplify each equation<BR>\n" );
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document.write( "3) (20 * d(2)) = (20 * d(1)) + (d(1) * d(2) * pi)<BR>\n" );
document.write( "4) (24 * d(2)) = (25 * d(1)) + (d(1) * (d(2) * pi)<BR>\n" );
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document.write( "solve equations 3 for d(1)<BR>\n" );
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document.write( "d(1) = (20 * d(2)) / (20 + d(2) * pi)<BR>\n" );
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document.write( "substitute for d(1) in equation 4<BR>\n" );
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document.write( "(24 * d(2)) = (25 + d(2) * pi) * (20 * d(2)) / (20 + d(2) * pi)<BR>\n" );
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document.write( "solve for d(2)<BR>\n" );
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document.write( "d(2) = 5 / pi<BR>\n" );
document.write( "d(1) = (20 * 5/pi) / (20 + (5/pi) * pi) = 4 / pi<BR>\n" );
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document.write( "C of fore wheel is pi * d(1) = 4 meters<BR>\n" );
document.write( "C of rear wheel is pi * d(2) = 5 meters<BR>\n" );
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document.write( "check answer<BR>\n" );
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document.write( "using equation 1 we have<BR>\n" );
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document.write( "(120 / 4) = (120 / 5) + 6<BR>\n" );
document.write( "30 = 24 + 6 = 30<BR>\n" );
document.write( "equation 1 checks<BR>\n" );
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document.write( "using equation 2<BR>\n" );
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document.write( "(120 / 5) = (120 / 6 ) + 4<BR>\n" );
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document.write( "24 = 20 + 4 = 24<BR>\n" );
document.write( "equation 2 checks<BR>\n" );
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document.write( " </SPAN>\n" );
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