document.write( "Question 1066540: The Sum of the digits of 3 digit number is 20. The middle digit is 1/4 of the sum of remaining two digits. If order of digits is reversed, the new number is more than earlier by 198. Find original number.
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Algebra.Com's Answer #681727 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! 100h+10t+u, the original number\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "System of equations literally from the description: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "The first two equations of this revised system will quickly give you the tens placed digit: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute for t=4 and revise:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Multiply this second equation by 99:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "ADD corresponding members \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Deleting earlier posted results....) \n" ); document.write( " \n" ); document.write( " |