document.write( "Question 1066540: The Sum of the digits of 3 digit number is 20. The middle digit is 1/4 of the sum of remaining two digits. If order of digits is reversed, the new number is more than earlier by 198. Find original number.
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Algebra.Com's Answer #681727 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
100h+10t+u, the original number\r
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\n" ); document.write( "\n" ); document.write( "System of equations literally from the description:
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\n" ); document.write( "\n" ); document.write( "\"system%28h%2Bt%2Bu=20%2C4t=h%2Bu%2C99u-99h=198%29\"
\n" ); document.write( "The first two equations of this revised system will quickly give you the tens placed digit: \"highlight%28t=4%29\"......\r
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\n" ); document.write( "\n" ); document.write( "Substitute for t=4 and revise:\r
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\n" ); document.write( "\n" ); document.write( "\"h%2Bu%2B4=20\"
\n" ); document.write( "\"h%2Bu=16\"
\n" ); document.write( "\"u%2Bh=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%2899u-99h=198%2Cu%2Bh=16%29\"
\n" ); document.write( "Multiply this second equation by 99:\r
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\n" ); document.write( "\n" ); document.write( "\"system%2899u-99h=198%2C99u%2B99h=1584%29\"
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\n" ); document.write( "ADD corresponding members
\n" ); document.write( "\"198u=1782\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28u=9%29\"\r
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\n" ); document.write( "\n" ); document.write( "(Deleting earlier posted results....)
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