document.write( "Question 1066507: x^2-3x-4>0 solve and write in interval notation \n" ); document.write( "

Algebra.Com's Answer #681695 by Boreal(15235) $\"\"$ $\"About$

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x^2-3x-4=0
\n" ); document.write( "(x-4)(x+1)= 0
\n" ); document.write( "x= 4
\n" ); document.write( "x=-1
\n" ); document.write( "-1 and 4 are critical points. They divide the number line into three areas: test less than the smallest, between them, and greater than the largest.
\n" ); document.write( "For x <-1 try -2. f(-2) >0
\n" ); document.write( "between the two points, try 0 f(0)< 0, does not work
\n" ); document.write( "greater than 4, try 5 f(5)=6
\n" ); document.write( "(-1, 4)
\n" ); document.write( " $\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-3x-4%29\"$
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