document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066460>Question 1066460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! \r<BR>\n" );
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document.write( "So, in my geometry class we are learning about special right triangles. (30,60,90 and 45,45,90). I recently took a quiz over the information and I was stuck on one problem. There is a 30,60,90 triangle, with the long leg as 10 square root three, and the short leg as X. The hypotenuse is y. The problem wanted you to solve for x and y. I tried using the rule of: short leg= x, long leg=x square root three, and the hypotenuse= 2x. Using that rule I got x as 10 and y as 20. Unfortunately this wasn't the right answer, and I was wondering if you could work through the problem, step by step to help me understand how to use the 30,60,90 rule and how it applies to this problem. \r<BR>\n" );
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document.write( "Thank you so much!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681640 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think from what the 30-60-90 special triangle comes from.  Or draw it.  The altitude of equilateral triangle cuts into two right triangles each congruent, of this 30-60-90 special right triangle type.\r<BR>\n" );
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document.write( "The short leg length is half the hypotenuse length.  If your short leg is x, and your hypotenuse is y, then  you have  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2F2=x ALIGN=MIDDLE  ALT=\"y%2F2=x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "As for getting the actual value of either x or y,  you should know what to do using the Pythagorean Theorem formula for right triangle.  <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28longLeg%29%5E2%2B%28shortLeg%29%5E2=hypotenuse%5E2 ALIGN=MIDDLE  ALT=\"%28longLeg%29%5E2%2B%28shortLeg%29%5E2=hypotenuse%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2810sqrt%283%29%29%5E2%2Bx%5E2=%282x%29%5E2 ALIGN=MIDDLE  ALT=\"%2810sqrt%283%29%29%5E2%2Bx%5E2=%282x%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=300%2Bx%5E2=4x%5E2 ALIGN=MIDDLE  ALT=\"300%2Bx%5E2=4x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2=300 ALIGN=MIDDLE  ALT=\"3x%5E2=300\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=100 ALIGN=MIDDLE  ALT=\"x%5E2=100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=10%29 ALIGN=MIDDLE  ALT=\"highlight%28x=10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Short leg, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=10 ALIGN=MIDDLE  ALT=\"x=10\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "hypotenuse, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2%2Ax=20 ALIGN=MIDDLE  ALT=\"y=2%2Ax=20\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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