document.write( "Question 1066400: the width of a rectangle is 5cm lesd than its lenght and its perimeter is 46cm. find width and area \n" ); document.write( "
Algebra.Com's Answer #681597 by addingup(3677)\"\" \"About 
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W = L-5
\n" ); document.write( "2L+2W = 46 substitute for W:
\n" ); document.write( "2L+2(L-5) = 46
\n" ); document.write( "2L+2L-10 = 46
\n" ); document.write( "4L = 56
\n" ); document.write( "L = 14
\n" ); document.write( "and
\n" ); document.write( "W = L-5 = 14-5 = 9
\n" ); document.write( "-----------------
\n" ); document.write( "L*W = Area
\n" ); document.write( "14*9 = 126
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