document.write( "Question 1066400: the width of a rectangle is 5cm lesd than its lenght and its perimeter is 46cm. find width and area \n" ); document.write( "
Algebra.Com's Answer #681597 by addingup(3677)![]() ![]() You can put this solution on YOUR website! W = L-5 \n" ); document.write( "2L+2W = 46 substitute for W: \n" ); document.write( "2L+2(L-5) = 46 \n" ); document.write( "2L+2L-10 = 46 \n" ); document.write( "4L = 56 \n" ); document.write( "L = 14 \n" ); document.write( "and \n" ); document.write( "W = L-5 = 14-5 = 9 \n" ); document.write( "----------------- \n" ); document.write( "L*W = Area \n" ); document.write( "14*9 = 126 \n" ); document.write( " \n" ); document.write( " |