document.write( "Question 1066413: 7 years ago x is 3 times older than y. Now
\n" ); document.write( "X is 5 times older tham y. What is the present age of X?
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Algebra.Com's Answer #681561 by Alan3354(69443)\"\" \"About 
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7 years ago x is 3 times older than y. Now
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\n" ); document.write( "1 time older = 2 times as old.
\n" ); document.write( "2 times older = 3 times as old.
\n" ); document.write( "3 times older = 4 times as old.
\n" ); document.write( "4 times older = 5 times as old.
\n" ); document.write( "5 times older = 6 times as old.
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\n" ); document.write( "7 years ago x was 4 times as old as y.
\n" ); document.write( "Now X is 6 times as old as y.
\n" ); document.write( "What is the present age of X?
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\n" ); document.write( "x-7 = 4*(y-7) = 4y-28
\n" ); document.write( "x = 6y
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\n" ); document.write( "x-7 = 4y-28
\n" ); document.write( "x = 4y-21
\n" ); document.write( "6y = 4y - 21
\n" ); document.write( "2y = -21
\n" ); document.write( "y = -10.5 years
\n" ); document.write( "x = -63 years\r
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