document.write( "Question 1066389: A number consists of two digits with a sum of 7 .If the number is increased by 3 it is equal to 11 times the tens digit. Find the number \n" ); document.write( "
Algebra.Com's Answer #681556 by Theo(13342)\"\" \"About 
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let a equal the tens digit.\r
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\n" ); document.write( "\n" ); document.write( "let b equal the ones digit.\r
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\n" ); document.write( "\n" ); document.write( "the sum of the digits is equal to 7.\r
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\n" ); document.write( "\n" ); document.write( "you get a + b = 7.\r
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\n" ); document.write( "\n" ); document.write( "the number itself is unknown.\r
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\n" ); document.write( "\n" ); document.write( "let x equal the number.\r
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\n" ); document.write( "\n" ); document.write( "that gets you 10 * a + b = x\r
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\n" ); document.write( "\n" ); document.write( "if the number is increased by 3 it is equal to 11 times the tens digit.\r
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\n" ); document.write( "\n" ); document.write( "that gets you x + 3 = 11 * a.\r
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\n" ); document.write( "\n" ); document.write( "since 10 * a + b = x, replace x with 10 * a + b to get 10 * a + b + 3 = 11 * a.\r
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\n" ); document.write( "\n" ); document.write( "solve for a to get a = b + 3.\r
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\n" ); document.write( "\n" ); document.write( "since a + b = 7, replace a with b + 3 to get b + 3 + b = 7.\r
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\n" ); document.write( "\n" ); document.write( "solve for b to get b = 2\r
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\n" ); document.write( "\n" ); document.write( "since a + b = 7, then a must be equal to 5.\r
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\n" ); document.write( "\n" ); document.write( "your number has to be 52.\r
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\n" ); document.write( "\n" ); document.write( "add 3 to it and you get 55.\r
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\n" ); document.write( "\n" ); document.write( "55 / 5 is equal to 11.\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.
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