document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066353>Question 1066353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the angle measures of any triangle is 180°.find each of the angle measures of a triangle if the second angle measures 10°more than twice the first,and the third angle measures 10°moree than the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681524 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find each of the angle measures of a triangle if the second angle measures 10°more than twice the first,and the third angle measures 10°moree than the second. <BR>\n" );
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document.write( "A = the 1st angle<BR>\n" );
document.write( "2A + 10 = 2nd angle<BR>\n" );
document.write( "2A + 20 = 3rd angle<BR>\n" );
document.write( "------------------------ Add<BR>\n" );
document.write( "5A + 30 = 180<BR>\n" );
document.write( "etc </SPAN>\n" );
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