document.write( "Question 1066350: A boat traveled downstream a distance of 50 mi and then came right back. If the speed of the current was 20 mph and the total trip took 3 hours and 20 minutes, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #681523 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = the speed of the boat with no current in mi/hr
\n" ); document.write( "\"+s+%2B+20+\" = the speed of the boat going downstream in mi/hr
\n" ); document.write( "\"+s+-+20+\" = the speed of the boat going upstream in miles/hr
\n" ); document.write( "Let \"+t+\" = time in hrs to go downstream
\n" ); document.write( "\"+10%2F3+-+t+\" = time in hrs to go upstream
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "Going downstream:
\n" ); document.write( "(1) \"+50+=+%28+s+%2B+20+%29%2At+\"
\n" ); document.write( "Going upstream:
\n" ); document.write( "(2) \"+50+=+%28+s+-+20+%29%2A%28+10%2F3+-+t+%29+\"
\n" ); document.write( "-----------------------------------
\n" ); document.write( "(2) \"+50+=+%2810%2F3%29%2As+-+200%2F3+-+s%2At+%2B+20t+\"
\n" ); document.write( "(2) \"+150+=+10s+-+200+-+3s%2At+%2B+60t+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+t+=+50%2F%28+s%2B20+%29+\"
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+150+=+10s+-+200+-+3s%2At+%2B+60t+\"
\n" ); document.write( "(2) \"+150+=+10s+-+200+%2B+t%2A%28+60+-+3s+%29+\"
\n" ); document.write( "(2) \"+150+=+10s+-+200+%2B+%28+50%2F%28+s%2B20+%29%29%2A%28+60+-+3s+%29+\"
\n" ); document.write( "(2) \"+350+=+10s+%2B+%28+50%2F%28+s%2B20+%29%29%2A%28+60+-+3s+%29+\"
\n" ); document.write( "(2) \"+350%2A%28+s%2B20+%29+=+10s%2A%28+s%2B20+%29+%2B+50%2A%28+60+-+3s+%29+\"
\n" ); document.write( "(2) \"+350s+%2B+7000+=+10s%5E2+%2B+200s+%2B+3000+-+150s+\"
\n" ); document.write( "(2) \"+10s%5E2+-+300s+-+4000+=+0+\"
\n" ); document.write( "(2) \"+s%5E2+-+30s+-+400+=+0+\"
\n" ); document.write( "\"+s+=+%28+-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+1+\"
\n" ); document.write( "\"+b+=+-30+\"
\n" ); document.write( "\"+c+=+-400+\"
\n" ); document.write( "\"+s+=+%28+-%28-30%29+%2B-+sqrt%28+%28-30%29%5E2-4%2A1%2A%28-400%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"+s+=+%28+30+%2B-+sqrt%28+900+%2B+1600+%29%29%2F2+\"
\n" ); document.write( "\"+s+=+%28+30+%2B-+sqrt%28+2500+%29+%29%2F2+\"
\n" ); document.write( "\"+s+=+%28+30+%2B+50+%29+%2F+2+\"
\n" ); document.write( "\"+s+=+80%2F2+\"
\n" ); document.write( "\"+s+=+40+\" ( can't use the negative solution )
\n" ); document.write( "--------------------
\n" ); document.write( "The speed of the boat with no current is 40 mi/hr
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+50+=+%28+s+%2B+20+%29%2At+\"
\n" ); document.write( "(1) \"+50+=+%28+40+%2B+20+%29%2At+\"
\n" ); document.write( "(1) \"+50+=+60t+\"
\n" ); document.write( "(1) \"+t+=+5%2F6+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+50+=+%28+s+-+20+%29%2A%28+10%2F3+-+t+%29+\"
\n" ); document.write( "(2) \"+50+=+%28+40+-+20+%29%2A%28+10%2F3+-+t+%29+\"
\n" ); document.write( "(2) \"+50+=+20%2A%28+10%2F3+-+t+%29+\"
\n" ); document.write( "(2) \"+50+=+200%2F3+-+20t+\"
\n" ); document.write( "(2) \"+150+=+200+-+60t+\"
\n" ); document.write( "(2) \"+60t+=+50+\"
\n" ); document.write( "(2) \"+t+=+5%2F6+\"
\n" ); document.write( "OK\r
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