document.write( "Question 1066335: A jet plane traveling at 500 mph over takes a propeller plane traveling at 200 mph
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Algebra.Com's Answer #681510 by ikleyn(52790)\"\" \"About 
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document.write( "d = \"%28%282%2A200%29%2F%28500-200%29%29%2A500\" = \"%28400%2F300%29%2A500\" = \"2000%2F3\" = 666.66 miles.\r\n" );
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document.write( "2*200 in the numerator is the distance \"ahead\" for the slower plane at the moment when the faster plane starts.\r\n" );
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document.write( "The difference 500-200 = 300 in the denominator is the relative speed.\r\n" );
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document.write( "The ratio \"%282%2A200%29%2F%28500-200%29\" is the time for the faster plane to catch the slower one.\r\n" );
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document.write( "The very left side of the formula is the distance at which the faster plane catches the slower one.\r\n" );
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