document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066327>Question 1066327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have 25 coins consisting of dimes and quarters. You have a total of $5.95. How many dimes and how many quarters do you have? Solve using a system of equations.\r<BR>\n" );
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document.write( "It would be great if you could answer this for me thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681487 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the substitution method:<BR>\n" );
document.write( "d+q = 25 subtract d from both sides:<BR>\n" );
document.write( "q = 25-d<BR>\n" );
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document.write( "0.10d+0.25q = 5.95 substitute for q:<BR>\n" );
document.write( "0.10d+0.25(25-d) = 5.95<BR>\n" );
document.write( "0.10d-0.25d+6.25 = 5.95<BR>\n" );
document.write( "-0.15d = -0.30 divide both sides by -0.15 and remember -/- = +<BR>\n" );
document.write( "d = 2 You have 2 dimes<BR>\n" );
document.write( "q = 25-d = 25-2 = 23<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "0.25(23) = 5.75<BR>\n" );
document.write( "0.10(2) = 0.20<BR>\n" );
document.write( "Total . . .5.95 Correct </SPAN>\n" );
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