document.write( "Question 1066312: Define two variables. Write two equations and solve.
\n" ); document.write( "The length of required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if it is known that the difference between its length and width is 50 meters? I'm
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Algebra.Com's Answer #681480 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
If y is length and x is width, then \"y-x=50\".\r
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\n" ); document.write( "\n" ); document.write( "Assuming the missing part of the description is \"fence material\" and is intended for the perimeter of 3000 meters, then \"2x%2B2y=3000\".\r
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\n" ); document.write( "\n" ); document.write( "Simplify that perimeter equation:
\n" ); document.write( "\"x%2By=1500\".\r
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\n" ); document.write( "\n" ); document.write( "You now have a simpler system of two equations in x and y.
\n" ); document.write( "\"system%28-x%2By=50%2Cx%2By=1500%29\"
\n" ); document.write( "which is easily solvable using the Elimination Method.
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