document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066237>Question 1066237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length or a rectangle is 15cm longer than its width. When its width is increased by 3cm and its length is decreased by 5cm, the area of the new rectangle is 20cm² bigger than the original rectangle. <BR>\n" );
document.write( "Find the original dimension of the new rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681460 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the rectangle. Then the length would be w+15. So:<BR>\n" );
document.write( "(w+3)(w+15-5)-w(w+15)=20<BR>\n" );
document.write( "w²+13w+30-w²-15w=20<BR>\n" );
document.write( "30-2w=20<BR>\n" );
document.write( "w=5<BR>\n" );
document.write( "The original rectangle was 5 x 20 cms., the new rectangle is 8 x 15 cms. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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